Question

A sample of argon gas at a pressure of and a temperature of, occupies a volume of. If the gas is heated at constant pressure until its volume is, the temperature of the gas sample will be  °C.

от и се спес 0 accc Ппрола напис п псиса по иппо чистио. A sample of argon gas at a pressure of 0.903 atm and a temperature of 137°C, occupies a volume of 805 mL. If the gas is heated at constant pressure until its volume is 1000 mL, the temperature of the gas sample will be °C.

Answer 1

Answer:

Step 1: Explanation:

We know the ideal gas equation, PV = nRT

where,

R=universal gas constant,T=temperature ,P=pressure,V=volume,n=moles.

=> PV = nRT

=> V/T=K where, K = constant [since nR and Pressure all are assume constant]

=> So, we have V1/T1 = V2/T2.

Step 2: Extract the data from the question

Given,

V1 = 805 mL    

T1= 137 °C = ( 137 +273.15) K = 410.15 K

V2= 1000 mL

T2 = we need to find and

Step 3: Calculation

By using above equation

V1/T1 = V2/T2.

=> T2 = V2T1 / V1

=> T2 = ( 1000 mL × 410.15 K) / 805 mL= 509.5 K = 236.35 °C

[ we got 509.5 K =>  509.5 K   = ( 509.5 K -273.15) °C = 236.35 °C ]

Hence, the new temperature is 236.35 °C