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[8 pts.] A solid sphere is placed at a height of 2.50 m on a ramp. The sphere is released from rest and rolls without slippin
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Answer #1

using conservation of energy

mgh = 0.5 m v^2 + 0.5 I w^2

mgh = 0.5 m v^2 + 0.5* ( 2/5) m r^2 ( v^2/r^2)

9.8* 2.5 = 0.5 v^2 + 0.2 v^2

v = 5.916 m/s

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