Question

What is the de Broglie wavelength (in nm) that you would from one molybdenum atom moving at a speed of 5 m/s? (Hint: Be careful with units. What is the mass of one molybdenum atom?) 0.832 nm 138 nm 1.38 nm 8.32x10 nm 1.38x10-27 nm 832 nm

Answer 1

What is the de-Broglie wave length (in nm) that you would from one malybdenum atom moring at a speed of 5 m/s ? (Hint: Be careful with units. What is the mass of one malybdenum atom a ) Correct answer = 0.832 nm) Solution. for solving we should know this the type of Question first De-Broglie equation. where, h = Plank's constant = 6.626x103 Joule second m= mass of the atom (kg.) - Velocity of the atom (in m/s) x= wave length of atom (in meter) since we come on our question The velocity of molybdenum atom= v= 5 m/s since the mass of 1 malybdenum atom= 95.94 amu { Tamu = 1.661x 1027 kg}

SO) Mars of the I molybdenum atom z m= 95.94 XL:661 X 10 kg m= 15g. 356x1024 kg After knowing the value of the mass of one malybdenum atom and its velocity we can calculate the wave length of I molybdenum atom by using the equation ③ mv Put the value of him, and o = 6.626 X10 34 JS {: 17 = 2 kg. m7/5) 159.356 X10 27 kg x 5 m/s 6.626 X 10 34 kg. m² ls 796.70X10 27 kg. m/s x= 0.00032x107 m S..Inmato mi x = 0.832 x 10 m x=0.832 nm So, wave length of the one malybdenum atom = 0.832 nm
summary:

For solving this type of problem we should know de-broglie equation

Wavelength = h/m×v

Where:

h=Planck's constant =6.626×10^-34 J.s

m=mass of the atom(in kg)

v= velocity of atom (in m/s)

Wavelength = wavelength of atom (in m)

Since the mass of one molybdenum atom=95.94 amu=159.356×10^-27 kg

After knowing the mass and velocity of one molybdenum atom we can calculate the wavelength by using above formula.

Answer=0.832 nm