Question

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LET'S THINK Phenobarbital (C12 H12 N2Os; M = 232.2g/mol) is a weak acid (pKg = 7.4) used as a sedative and anticonvulsant. This drug is insoluble in water; the concentration of saturated aqueous solutions of this compound is close to 1 g/L pH Homework Unanswered Estimate the pH of a saturated solution of phenobarbital.

Answer 1

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for saturated solution. Walg, N= 1000ml , mw=232.2g Now, Molarity = Wx1000 = ixiolo (Mw) v (232.2) (1000) Molarity = 0.0043 M I Given pha= 7.4. u. kaz antilog (-7-4)= 3.98810-8 we have [H₂o+] = v kaxo = √3988108 x 0.0043 = 1.30x105. Now, pta-log (40+) = -log(1-30x106) = 4.88 TpH=4.88 PHx4.91