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A 752 mL sample of water was placed in a 1000 gram pan of aluminum. The...

A 752 mL sample of water was placed in a 1000 gram pan of aluminum. The initial temperature of the pan was 26 celsius and the final temperature of the system was 39 celsius. What was the initial temperature of the water? The specific heat of aluminim is 0.9025
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Answer #1

mass of water   = volume *density

                          = 752*1   = 752g

Heat lose of water               =            heat gain of pan of aluminum

mcDT                                    =               mcDT

752*4.184*(t-39)                    =               1000*0.9025*(39-26)

          t                                      =   42.73^0c

The initial temperature of water   = 42.73^0c>>>>answer

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