Question

Enough of a monoprotic acid is dissolved in water to produce a 1.29 M solution. The pH of the resulting solution is 2.80. Calculate the Ka for the acid. Ка

Answer 1

We will write equation for a acid dissolved in water and make ICE table to solve this problem.

Am HA + ho concentoution 1.29 m - PH: 2180 ² hot ta __ O O +x toch 1,29 - 2 1.29-3 ke = (Hot ICAJ CHA) - (X )(x) ___(1,29-4) x2 1.29-X k = — [Hot] : combilog tapm ankilog (-2.80) = 1.58 x 103 m = nch Ở eplace the value of x in ech ( ), k (1.58x1037 __1.29 - 1,58 X103 ka = 11.58 x 1032 - 1.94 x16 1.288

So, answer is Ka = 1.94× 10^-6 .

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