Using your data from the experiment, calculate the initial moles of HCl that you started with....
Using your data from the experiment, calculate the initial moles of HCl that you started with. ( for this problem you will use your initial concentration of HCl and your 50 mL volume to solve).
| Trial 1 | trail 2 | |
| Mass of KHP (KC8H5O4) (g) | .29 g | .21 g |
| Moles of KHP | .000422 | .00422 |
| Moles of NaOH | .01M | .01M |
| Volume of NaOH | .0247 | .0222 |
| Molarity of NaOH | .0575 | .0464 |
| Average molarity of NaOH | .0516 M | |
Homework Answers
Number of mole s= molarity * volume
Average volume of NaOH = 0.0247 +0.022
= 0.02345 mlNaOH
mole of NaOH = molarity * volume in L
= 0.1* 0.02345/1000
= 2.345*10^-6 mole NaOH
The recation between HCl and NaOH is as follows:
HCl + NaOH= NaCl+ H2O
Therefore 2.345*10^-6 mole NaOH reacts with 2.345*10^-6 mole of HCl
Molarity = number of moles / volume in L
Here volume of HCl= 50 ml
0.050 L
Thus
Molarity = 2.345*10^-6 mole HCl/0.050 L
= 4.69*10^-5 M
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