Find the indicated probability using the standard normal distribution. P(-0.93 < z <0.93) (Round to four decimal places as needed.)
P (-0.93 < z < 0.93) = P(-0.93 < z < 0) + P(0 < z < 0.93)
= 0.3238 + 0.3238
P (-0.93 < z < 0.93) = 0.6476
Find the indicated probability using the standard normal distribution. P(-0.93 < z <0.93) (Round to four...
Find the indicated probability using the standard normal distribution. P(-3.12<z<0) round to four decimals places as needed
Find the indicated probability using the standard normal distribution. Find the indicated probability using the standard normal distribution. P(-0.39<z<0) Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. P(-0.39<z<0)= (Round to four decimal places as needed.)
Find the indicated probability using the standard normal distribution. P(-1.07 "z 1.07) Click here to view page 1 ofthe standard Click here to view P(-1.07 kz1.07) (Round to four decimal places as needed.) table.
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(z ≤ −1.94) = [x].
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(−2.12 ≤ z ≤ −0.41) =
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(−2.07 ≤ z ≤ −0.49) =
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(−1.14 ≤ z ≤ 2.63) =
Let z be a random variable with a standard normal distribution. Find the indicated probability. (Round your answer to four decimal places.) P(−1.24 ≤ z ≤ 2.64) = Shade the corresponding area under the standard normal curve.
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For the standard normal distribution shown on the right, find the probability of z occurring in the indicated region. 0.61 -0.93 z A normal curve is over a horizontal z-axis. Vertical line segments extend from the horizontal axis to the curve at negative 0.93 and 0.61. The area under the curve between negative 0.93 and 0.61 is shaded. The probability is nothing. (Round to four decimal places as needed.)