Given that, mass of acron m = 3117 g Whentall from tree it found at boint at poin A kinetic Energy K = 0.299 J Potential Energy W = 0.167 J A. Aon cround lahe know that, if mass m at height h from ground then it's potential Energy can be written as W = mgh =) uxh. So, when height from ground decreas, the Potential Energy of acson will decrease. Now by the conservation Law of Energy it's Total Mechanical Energy (ktu will be constant. rence -K+U= Constent =E
So, If acron falls, it Potential Energy will decrease and kinetic Energy will increasin and Hence, " Potential energy decreases - Kinotic energy increases." Now, - When acron hit the ground, it's Polential Energy [u=o] So it's kinetic energy - Totul energy Kraund 20.299 + 0.167 Total Kinetic Energy K = 0.466 J, godind
Now, E Mass of apple m = Toing and it falls from Same height as acron, then for acron Ua mgh 0.466= mgh 2 h For Apple C = me 9 -3 Godina apple a acreen QUE
Now device equation (3 by equatican Van magh 2 mg 0 1466 mgh orare ma=70.2 g Ua= 7012 801466 F3117 = 3.179 az e10.3196 J = Eal When apple hit the goceend, by Law of Conservation of energy, it's total Energy converted into Kinetic Energg.
so K appe = Ea (Total Energy of Apple) 1 Kapple = 10,3196 Je / Konto 0.466. J But 'arccon Hence, " When apple hit the ground it's kintic Energy is different from Kinetic Energy of acron." option "No" is correct,