![Given that, mass of acron m = 3117 g Whentall from tree it found at boint at poin A kinetic Energy K = 0.299 J Potential Ener](//img.homeworklib.com/questions/75e8cb50-70d9-11ea-83c0-ad8bbf797206.png?x-oss-process=image/resize,w_560)
![So, If acron falls, it Potential Energy will decrease and kinetic Energy will increasin and Hence, Potential energy decreas](//img.homeworklib.com/questions/7698fa50-70d9-11ea-bc53-2b3765f68c5f.png?x-oss-process=image/resize,w_560)
![Now, E Mass of apple m = Toing and it falls from Same height as acron, then for acron Ua mgh 0.466= mgh 2 h For Apple C = me](//img.homeworklib.com/questions/77468620-70d9-11ea-ad79-bb91739ffa26.png?x-oss-process=image/resize,w_560)
![Now device equation (3 by equatican Van magh 2 mg 0 1466 mgh orare ma=70.2 g Ua= 7012 801466 F3117 = 3.179 az e10.3196 J = Ea](//img.homeworklib.com/questions/77e80430-70d9-11ea-a02b-a3fa6afa728c.png?x-oss-process=image/resize,w_560)
![so K appe = Ea (Total Energy of Apple) 1 Kapple = 10,3196 Je / Konto 0.466. J But arccon Hence, When apple hit the ground](//img.homeworklib.com/questions/78851e60-70d9-11ea-822d-ef6bf8bc17fc.png?x-oss-process=image/resize,w_560)
Given that, mass of acron m = 3117 g Whentall from tree it found at boint at poin A kinetic Energy K = 0.299 J Potential Energy W = 0.167 J A. Aon cround lahe know that, if mass m at height h from ground then it's potential Energy can be written as W = mgh =) uxh. So, when height from ground decreas, the Potential Energy of acson will decrease. Now by the conservation Law of Energy it's Total Mechanical Energy (ktu will be constant. rence -K+U= Constent =E
So, If acron falls, it Potential Energy will decrease and kinetic Energy will increasin and Hence, " Potential energy decreases - Kinotic energy increases." Now, - When acron hit the ground, it's Polential Energy [u=o] So it's kinetic energy - Totul energy Kraund 20.299 + 0.167 Total Kinetic Energy K = 0.466 J, godind
Now, E Mass of apple m = Toing and it falls from Same height as acron, then for acron Ua mgh 0.466= mgh 2 h For Apple C = me 9 -3 Godina apple a acreen QUE
Now device equation (3 by equatican Van magh 2 mg 0 1466 mgh orare ma=70.2 g Ua= 7012 801466 F3117 = 3.179 az e10.3196 J = Eal When apple hit the goceend, by Law of Conservation of energy, it's total Energy converted into Kinetic Energg.
so K appe = Ea (Total Energy of Apple) 1 Kapple = 10,3196 Je / Konto 0.466. J But 'arccon Hence, " When apple hit the ground it's kintic Energy is different from Kinetic Energy of acron." option "No" is correct,