Solution :
n = 200
x = 120
= x / n = 120 / 200 = 0.600
1 - = 1 - 0.600 = 0.400
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.960
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.960 * (((0.600 * 0.400) / 200)
= 0.068
A 95 % confidence interval for population proportion p is ,
- E < P < + E
0.600 - 0.068 < p < 0.600 + 0.068
0.532 < p < 0.668
( 0.532, 0.668)
Construct a 95% confidence interval of the population proportion using the given information. x = 120,...
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