Question

Construct a confidence interval of the population proportion at the given level of confidence. x- 120, n 1200, 99% confidence The lower bound of the confidence interval is (Round to three decimal places as needed.) The upper bound of the confidence interval is (Round to three decimal places as needed.)

Answer 1

PART (A)

99% Confidence Interval for p x 120 = 1200 = 1 = 1/10 = 0.1 Significance level = a = 1- confidence = 1 -0.99 = 0.01 Critical z-value = 20/2 = 20.01/2 = 20.005 = 2.58 (closest value From z table) Standard error of P: SE X (1-P) 0.1 x 0.9 12000.00866 E = 2/2 X = 2.58 x 0.00866 -0.022343 Margin of Error, E = 0.0223 99% Confidence Interval is given by 0.1 +0.022343 Lower limit = D-E=0.1 -0.022343 0.077657 Upper limit = +E= 0.1 +0.0223430.122343 99% CI for p : 0.078 <p < 0.122 Note that exact using technology answer is: 0.1 invNorm(0.01/2) x sqrt((0.1 (0.9)/1200) (0.0776926639, 0.1223073361)

Port B x = los n=190 ICO P=0.70 99% confidence internal for population Proportion. p is = p" + (7224) p. m ) = 0.70 + (2.575 x Jo-7ox 0:30 The 99% confidence intertel is (0.6o4, 0.794) lower bound -10.604] upper bound = 10.796) ISO Notes I Hope your Happy with my Auswer & please suffert me with your Ratong. Thank you