Question

3.0 kg Problem #2 The coefficient of kinetic friction between the 3.0 kg block in figure and the table is 0.29 and it is observed that the 4.0 kg block is accelerating downward 4.0 kg 2.0 kg 1. The value of the magnitude of the acceleration of the blocks in m/s is closest to a. 0.056 b. 1.23 c. 2.30 d. 4.20

Answer 1

Ans Ti mi = 319 Dating mga 4kg.. Given by , The Coefficient of kinetic friction between 3 kg block and the table is. M. = 0.29 the 7 Force acted upon on A, B and c is described by the above figure. The cauction of motion of À Block is T. - mag ama [ais ccceleration] 5 Ti - 2924 Ľ: m20.2137. des T, 22(944) – 0. row, the friction force F MR [since R.is = 0.29*3 normal reachim imperme 0.879 i Ramig 7 of a Bolck is The - De eauation of motion T2 - T - f = mora o TZ - T, = f + mia

1. - 1, 0.874 + 36 ' The couaim of motion - of c izlock is hty: mzy - "T,, : mga - 29 -15ona Ľ: mp369 69] 7 - Ty o 40-0) -- 0 ③ + ② + ③ them we get. Ti + T, - ; - Ty - rj +2a 401814 + 3a Now, 440 -40 ga - 139 20" z gap 1:139 za 113 x 9og i p1 = 9.8 m/s2) Ta 2.923 m/s2 ans optim.b is correct. A The value of magnitude of acceleration of the blocks is 4123 m/s2, b 27 from eaustion - 1, we get - Tea 410-0) "inside 3-4x8.57 - T2 = 34.28

" T2 z 34.28 a 34:3 L Ta a 34.3 Newton Ans The . option tension in the From re auction - -a is correct. string attached to the 4kg mass is 34.3 Newton we get ③. TI = 219+) 5 T, 2 29.84 1.23) N. a T, 2 X 11.03 nr 4 To 22.06 Newton | ns. obtion -c is correct. ed to je : The tension in the string attache 2 kg mass is 22.060 or 2200 Newton.