Calculate the concentration of buffer components present in 177.00 mL of a buffer solution that contains 0.350 M NH4Cl and 0.350 M NH3 immediately after the addition of 1.30 mL of 6.00 M HNO3.
Part 1:
[NH3]=
Part 2:
[NH4+]
mol of HNO3 added = 6.0M *1.3 mL = 7.8 mmol
NH3 will react with H+ to form NH4+
Before Reaction:
mol of NH3 = 0.35 M *177.0 mL
mol of NH3 = 61.95 mmol
mol of NH4+ = 0.35 M *177.0 mL
mol of NH4+ = 61.95 mmol
after reaction,
mol of NH3 = mol present initially - mol added
mmol of NH3 = (61.95 - 7.8) mmol
mol of NH3 = 54.15 mmol
mol of NH4+ = mol present initially + mol added
mol of NH4+ = (61.95 + 7.8) mmol
mol of NH4+ = 69.75 mmol
Total volume = 177 mL + 1.30 mL = 178.30 mL
So,
[NH3] = mol of NH3 / total volume
= 54.15 mmol / 178.30 mL
= 0.304 M
[NH4+] = mol of NH4+ / total volume
= 69.75 mmol / 178.30 mL
= 0.391 M
Answer:
[NH3] = 0.304 M
[NH4+] = 0.391 M
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