Question

1) True or False? Carver Memorial Hospital's surgeons have a new procedure that they think will decrease the time to perform an appendectomy. A sample of 8 appendectomies using the old method had a sample mean of 38 minutes with a sample variance of 36 minutes, while a sample of 10 appendectomies using the experimental method had a sample mean of 29 minutes with a sample variance of 16 minutes. For a right-tailed test comparing two population means (assume equal population variances) where H0: u0-u1 is less than or equal to 0, H1: u0 -u1 is greater than 0, we can reject the null hypothesis at alpha =0.05.

2) True or False? Kate asked each student in her psychology class how many children he or she considered ideal for a married couple and obtained the Excel results shown below a alpha =.05. According to the table, we can conclude that we can reject the null hypothesis of equal population means (here, h0: an average men want the same number of children as women).

3) True or False? In constructing a confidence interval for the difference of two population proportions, we must use a critical value ( for the upper alpha/2 area) from the standard normal distribution.

4) Analysis of variance (ANOVA) is a technique used to test for

a) equality of two or more variances

b) equality of two or more means

c) equality of a population mean and a given value

d) equality of more than two variances

5) True or False? Refer to the following partial one factor ANOVA results from excel ( some information is missing). The number of treatment groups must be 4.

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F Statistic
Between Groups			210.2788
Within Groups	1483		74.15
Total	2113.833

Answer 1

(1) Answer:True Since, the time taken for surgery using the new procedure is taking less time, so that the difference of old and new is greater than zero, that is. Ho-4-4 0, H1-4-.4 > 0 21 Answer.True (3\Answer; True 100(1- )%confidence interval for thedifferenceof proportions (P-Pa) is (4)Answer:(b)Equality of two more means. (5)Answer: True ANOVA table Source of Variati on Between GrOups 210.2788 DF MS 630.833 210.2788 -3 2113.833-1483- 630.833210.2788 -2.836 74.15 1483 20 74.15 Within Groups(Error) 1483 74.15 Total 23 2113.833