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4. An orange 102 mm in diameter having a surface temperature of 21.1°C is placed on an open shelf in a refrigerator held at 4
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page:oi Answer: @ Given information, The diameten of orange , d = 0.102cm Surface temperature Tw= 16°c. Toru°C R=0.051m We capage:02 = 1.3+(ialo.us) 14 = 1348 235.2934 = 1:37 * 3.9165 The 5.365 then, A = UTR zut(0.05) zuer x (a.5x163) A = 0.03111 m?

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