Answer : The answer is option a.
For strategy A the payoffs are a11 and a12 . Now strategy A will be a strictly dominant strategy if strategy A's all payoffs become greater than (>) the strategy B's or strategy C's payoffs. Given option a shows that the strategy A's payoffs are greater than the strategy B's payoffs. Therefore, option a is correct.
QUESTION 3 Player 2 a11, b11 а12, b12 Player 1 a21, b21 a22, b22 C аз1, bз1 аз2, b32 Consider the game in normal form in the picture above. For strategy A to be the (strict) dominant strategy it is sufficient that | a. a11 a21 and a12 > a22 b. None of the other answers apply. Ca11>b11 and a12 > b11 . d.a11 a21 and a11> a31 . ABI
QUESTION 3 Player 2 D A a11, b11 a12, b12 Player 1 a21, b21 a22, b22 аз1, bз1 аз2, bз2 Consider the game in normal form in the picture above. For strategy A to be the (strict) dominant strategy it is sufficient that a. a11 > a21 and a12 > a22 · D.a11 > a21 and a11 > a31 · C. None of the other answers apply. a11 > b11 and a12 > b11 .
Let 1) a11 x1 + a12 x2 + a13 x3 = b1 2) a21 x1 + a22 x 2+ a23 x3 = b2 3) a31 x1 + a32 x 2+ a33 x 3 = b3 SHOW that if det(A) does not equal 0, where det (A) is the determinant of the coefficient matrix, then x2= det(A2)/det(A) where det (A2) is the determinant obtained by replacing the second column of det (A) by (b1, b2, b3) to the power T.