Question

How much heat must be extracted from 750 mL of white wine to cool it from 25 °C to 13 °C, if the wine is 9.6% ethanol by weight? Assume the wine can be treated as an aqueous solution of ethanol, with no other components. The molar heat capacity of water is 75.4 J/mol K and of ethanol is 112.1 J/mol K. Also: Show that this corresponds to a wine that is 12% alcohol by volume, or ABV. Clearly state sources for any data used please.

Answer 1

AT 25-13 = 12. Density of ethancel - 789 kq/m3) (914) [source=google] Density of Wales - 1000kg /m)(82) Let the mass of wine be x gram. mass of ethanol in it in 9.6 xx. gr. as rest is water So, mass of water, - X- 0.096 x = 0.90ux. 700 Volume of water I 0.904x ml. volume of ethanol = (750-0.904x) mL. Density - mass Volume 0.789 g = 0.096 x g. ML (750-0.904x) mL.. 591.75 -0.13 X = 0.096 x 1x - 731.457 - mass of wine - 731045 g. mass of ethanol = 9.6 x 731045. 100 = 70.2192 g Mass % water 73145-70.219. = 6612319

18 males of water = 661.23 - - 36.73 mol. males of ethanol = 70.22 46 = 1.52 mol. Heat extracted from water, Ou RCAT = 36.73 x 7504 x12 Own 33-23 KJ. Heat extracted from ethanol. le= nCAT 1052 x 112.7 x 12. de = 2.044 KI. Tatal Heat low + de = 35.27K T.. volume of ethool in wine - mass. density 5 70.22 0.789 TV = 899mL of

% volume of ethanol - Disco 89.9 x 100 % 750 %. %1/0= 12