specific heat of Al = 0.921J/g.K
mass of Al = 18.2 g
Heat given by Al = mass x sp. heat x difference in
temperature
= 18.2g x 0.921J/g.K [ T -97.06]K
Heat absorbed by water = 80.4g x 4.184J/g.K [ T-21.1]K
As
- heat given by Al = heat absorbed by water
-16.7622[T-97.06] = 336.39 [T-21.1]
solving T = 24.70 C
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