m(water) = 78.8 g
T(water) = 22.01 oC
C(water) = 4.184 J/goC
m(Mg) = 19.9 g
T(Mg) = 97.83 oC
C(Mg) = 1.02 J/goC
T = to be calculated
Let the final temperature be T oC
use:
heat lost by Mg = heat gained by water
m(Mg)*C(Mg)*(T(Mg)-T) = m(water)*C(water)*(T-T(water))
19.9*1.02*(97.83-T) = 78.8*4.184*(T-22.01)
20.298*(97.83-T) = 329.6992*(T-22.01)
1985.7533 - 20.298*T = 329.6992*T - 7256.6794
T= 26.41 oC
Answer: 26.41 oC
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