a solid object is formed by rotating the shaded area 360° about the x axis. A)...
Part A Determine the surface area formed by revolving the shaded area 360° about the z asis. (Figure 1) Express your answer to three significant figures and include the appropriate units. DIA * O ? A- Value Units Submit Request Answer Part B Determine the volume of the solid formed by revolving the shaded area 360° about the z axis. Express your answer to three significant figures and include the appropriate units. Value Units
Locate the centroid of the volume obtained by rotating the shaded area about the x-axis. y y=kx1/4 5 2 -h
Use cylindrical shells to find the volume of the solid formed by rotating the area between the graph of x=y^(9/4) and x=0, 0≤y≤1 about the x-axis.
Find the area of the surface obtained by rotating the given curve about the x-axis. x = 20 cos (0), y = 20 sinº (0), 0 <O< 2 Preview
Find the surface area of the solid of revolution obtained by rotating the curve x=(1/12)(y^2+8)^(3/2) from ?=2 to ?=5 about the x-axis: (1 point) Find the surface area of the solid of revolution obtained by rotating the curve X= +8)3/2 from y = 2 to y = 5 about the x-axis:
2. Find the surface area of the object obtained s 2 about the y-axis. by rotating y: 478x2,15*
Use cylindrical shells to find the volume of the solid formed by rotating the area between the graph of y; and x = 0,0 < y < 1 about the x-axis. = Volume - s": f(y)dy where, f(y) = Preview What is the volume? Preview
Find the volume of the solid generated by revolving the shaded region about the given axis. About the x-axis 20 18 16- 14 12 10. y=9- x2 4 Find the volume of the solid generated by revolving the shaded region about the given axis. About the x-axis 20 18 16- 14 12 10. y=9- x2 4
Calculate the moment of inertia of the shaded area about the x-axis.
find the volume of the solid of revolution generated by rotating the given area about the given axis x y22, y + 4; about the line 1 (ignore the lines in the area) = 2 y22 1 6 4 -1 x y22, y + 4; about the line 1 (ignore the lines in the area) = 2 y22 1 6 4 -1