Question

A 185.0 mL solution of 2.714 M strontium nitrate is mixed with 215.0 mL of a 3.460 M sodium fluoride solution. Calculate the mass of the resulting strontium fluoride precipitate.

mass:

g

Assuming complete precipitation, calculate the final concentration of each ion. If the ion is no longer in solution, enter a 0 for the concentration.

[Na+]=

M

[NO−3]=

M

[Sr2+]=

M

[F−]=

M

Answer 1

hlaite a balanud chamical egualuen S& (NO3) taNaF Sa +2 NaND3 calculate mo of mols fer sst2 mats = Valume x Molaity (motj 2.714 x 0.185 0.50209 mole 3.460 X0.21S 0.7439 mole 2Mole af F Loill give (piecipital oles 4 ole CS Scanned with S&t2 CamScanner E is the imiting seaotant

Calculate theoetcal mas ok SaF 0-439 molFx mol St 2molF 46.2 43 X 195.62-9mel 14 mols pin alution Moles Na 11 07439 mol D.4 L 18.597 mollL volume 185+a15 f00me 0-4e Moles of No3 1.004mel ENGEJ 1.004mel 0.4L 2.51 mol L Scanned with CS CamScanner

Lonc 0.50209 mal Sa+ 0.7439 Tnitially Sol contained moles Sat2 plecipitated 0.37 19 S2 ppt moles a Si semaining in sol- 0.50209- 0.3319 0.13019 mee 0.13019 04 0.3254 M 218 0x 08 CamScanner