What is the E cell for the cell represented by the combination of the following half-...
0 What is the Ecell for the cell represented by the combination of the following 4) half-reactions? 2Hg2+(aq) + 2e-→Hg22+(aq) Cr3t(ag)+3eCr(s) E-0.92 V B) 1.28 V 9) 0.18 V A) 2.12 V D) 1.66 V E)-0.18 V 5) Examine the following half-reactions and select the weakest oxidizing agent among the 5)_ species listed. E。= 0.854 V E1.185 V K+(aq) + e-→ K(s) F20(aq) + 2H+(aq) + 4e-→ 2p-(aq) + H20() E。= 2.153 V A) F2o(ag) B) AuBr4Taq) C) Mn2+(ag) D)...
Draw the voltaic cell that will give the most positive cell potential choosing from the following half reactions: Eo (vs. SHE) Zn2+ (aq) + 2e- Zn (s), Eo= -0.76 Al3+ (aq) + 3e- Al (s), Eo= -1.66 Cr3+ (aq) + 3e- Cr (s), Eo= -0.74 Co2+ (aq) + 2e- Co (s), Eo= -0.28
Given the following half reactions what is the voltage of the galvanic cell that would result from their combination [maximum positive voltage and spontaneous reaction). Show work. E° (volts) -0.74 Cr3+ (aq) + 3e Cu2+ (aq) + 2e → → Cr (8) Cu (s) +0.34 And what is the overall reaction that results after the half reactions are combined to cancel all electrons. Show work. And fill in the following abbreviated cell to represent the actual galvanic cell from above.
Table 20.2 Half-reaction E° (V) Cr3+ (aq) + 3e- → Cr (s) -0.74 Fe2+ (aq) + 2e- Fe () -0.440 Fe3+ (aq) + e- → Fe2+ (s) +0.771 Sn4+ (aq) + 2e- Sn2+ (aq) +0.154 The standard cell potential (Eºcell) for the voltaic cell based on the reaction below is V. Cr (s) + 3Fe3+ (aq) + 3Fe2+ (aq) + Cr3+ (aq) A) -1.45 B) +2.99 C) +1.51 D) +3.05 E) +1.57
3. Calculate the cell potential for the voltaic cell based on the following half reactions at T = 25°C: Cr3+(aq) + 3e Cr(s) E° = -0.74 V TiO2(aq) + 2H(aq) + 1e → Ti+(aq) + H2O(1) E° = + 0.10 V Where, [Cr3+] = 1.0 x 104 M, [TiO2+] = 1.0 x 10-1M, [H+] = 1.0 M, [Ti$+] = 5.0 x 10-2 M.
Given the two following half reactions, Cr(aq) + 3e- → Cr(s) E° = -0.74 V Hg2(aq) + 2e- → Hg(l) E° = +0.80 V calculate the standard emf for the following cell: Cr | Cr|| Hg2| Hg
2. Using the information provided, calculate the standard cell potential, Eºcell, for the reaction below: Half-reaction Cr3+ (aq) + 3e- → Cr(s) Fe2+ (aq) + 2e- → Fe(s) Fe3+ (aq) + e- + Fe2+ (s) Sn4+ (aq) + 2e- + Sn2+ (aq) E° (V) -0.74 -0.440 +0.771 +0.154 3Sn(aq) +2Cr(s) →2Cr" (aq) +35n²+ (aq)
help with this one Construct a galvanic cell using the following half-reactions: Cr3+ (aq) + 3e - Cr(s) º = -0.56 V 2 Hg2+(aq) + 2e - H922+(aq) = 0.92 V 2 Ho2+ The initial concentrations are: [Cr3+] =0.31 M [Hg2+] =2.57 M [Hg22+] =0.49 M (1) What is the potential of this non-standard cell at 298 K? Give your answer to 3 sig. figs. E(V) = Submit Answer Tries 0/2 (ii) How will each of the following changes to...
Use the following half-reactions to write 3 spontaneous reactions, calculate E°cell for each reaction, what is the n number (number of electrons transferred). Au+ (aq) + e− → Au (s) E° = 1.69 V N2O (g) + 2H+ (aq) + 2 e− → N2 (g) + H2O (l) E° = 1.77 V Cr3+ (aq) + 3 e− → Cr (s) E° = -0.74 V Question 7 0.36 pts Use the following half-reactions to write 3 spontaneous reactions, calculate Eºcell for...
The standard reduction potentials of the following half-reactions are given in Appendix E in the textbook: Ag+(aq)+e−→Ag(s)= .799 Cu2+(aq)+2e−→Cu(s)= .337 Ni2+(aq)+2e−→Ni(s)= -.28 Cr3+(aq)+3e−→Cr(s). = -.74 1. Determine which combination of these half-cell reactions leads to the cell reaction with the largest positive cell emf. 1st and 2nd, 1st and 3rd, 1st and 4th, 2nd and 3rd, 3rd and 4th. It isn't the first or last one because I have gotten it wrong twice. 2. Calculate the value of this emf....