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5. MF: C10H14O2 IR 10 oo 4000 H NMR: 6.9 ppm (doublet; integral 2), 6.8 ppm (doublet; integral 2), 3.6 ppm (doublet; integra

deduce the structure that corresponds to the following data

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Answer J Molecalas Fosmala. Cio H402 Deqsee ok Unsalurahon- No.ok C+1)-Noo H) 2 (LoH 11-7 -4 he given Compaund have Four cle

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deduce the structure that corresponds to the following data 5. MF: C10H14O2 IR 10 oo 4000...
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