Question

Jim has to select one of the two call centers to handle customer service for his...

Jim has to select one of the two call centers to handle customer service for his business. The call center B charges more than the call center A with the claim that their (B’s) rating for call satisfaction is very high. Jim obtains the contacts of randomly selected callers for the two companies and ask the level of satisfaction on a 0-10 scale to test the hypotheses (symbols have their usual meaning) The data are below Satisfaction ratings A 6.6 6.6 7.1 4.8 4.8 9.0 7.6 8.3 6.3 5.6 6.9 Satisfaction ratings B 8.8 8.3 8.5 8.1 8.0 8.7 8.0 8.8 7.9 8.6 8.0 8.6 Consider the side by side box plots given below a) do you see any strong outliers? b) test the above hypotheses at 1% level of significance, write the test statistic, and the P_value.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution:-

Sum Mean S.D Count S.E 72.6 100.3 6.6 8.3583333333 1.3401492454 0.3449857265 0.4040702009 0.0995888010

State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.

Null hypothesis: uA> uB
Alternative hypothesis: uA < uB

Note that these hypotheses constitute a one-tailed test.

Formulate an analysis plan. For this analysis, the significance level is 0.01. Using sample data, we will conduct a two-sample t-test of the null hypothesis.

Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).

SE = sqrt[(s12/n1) + (s22/n2)]
SE = 0.4162
DF = 21

t = [ (x1 - x2) - d ] / SE

t = -4.25

where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is thesize of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between population means, and SE is the standard error.

The observed difference in sample means produced a t statistic of -4.25.

Therefore, the P-value in this analysis is less than 0.0001.

Interpret results. Since the P-value (almost 0) is less than the significance level (0.01), we have to reject the null hypothesis.

From the above test we have sufficient evidence in the favor of the claim that call center B charges more than the call center A with the claim that their (B’s) rating for call satisfaction is very high.

Add a comment
Know the answer?
Add Answer to:
Jim has to select one of the two call centers to handle customer service for his...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 1) Do you think there is a linear correlation between Movie Ratings and their Runtimes?

    Movie Ratings8.78.97.67.27.28.18.86.88.79.08.57.98.79.19.07.28.47.57.79.09.38.76.99.28.49.29.09.18.98.29.48.38.17.99.18.78.67.88.47.8Movie runtimes201124136155131161110132116136911279612612913512411617012117511818911713610819589881221191161261151531431181291441321) Do you think there is a linear correlation between Movie Ratings and their Runtimes? Explain why or why not before doing any work!2) Is there a linear correlation between the data based on the correlation coefficient? Explain.3) Find the linear regression line and explain what it means in English.4) Perform a hypothesis test at the 5% level of significance to see if a correlation is significant.

  • The data contained in the file named StateUnemp show the unemployment rate in March 2011 and...

    The data contained in the file named StateUnemp show the unemployment rate in March 2011 and the unemployment rate in March 2012 for every state.† State      Unemploy- ment Rate March 2011        Unemploy- ment Rate March 2012 Alabama              9.3          7.3 Alaska 7.6          7.0 Arizona                 9.6          8.6 Arkansas              8.0          7.4 California             11.9       11.0 Colorado              8.5          7.8 Connecticut        9.1          7.7 Delaware             7.3          6.9 Florida 10.7      ...

  • A particular talent competition has five judges, each of whom awards a score between 0 and...

    A particular talent competition has five judges, each of whom awards a score between 0 and 10 to each performer. Fractional scores, such as 8.3, are allowed. A performer’s final score is determined by dropping the highest and the lowest score received then averaging the three remaining scores. Write a program that does the following: 1. Reads names and scores from an input file into a dynamically allocated array of structures. The first number in the input file represents the...

  • 11.38  Building a multiple linear regression model. Let’s now build a model to predict the life-satisfaction...

    11.38  Building a multiple linear regression model. Let’s now build a model to predict the life-satisfaction score, LSI. (a) Consider a simple linear regression using GINI as the explanatory variable. Run the regression and summarize the results. Be sure to check assumptions. (b) Now consider a model using GINI and LIFE. Run the multiple regression and summarize the results. Again be sure to check assumptions. (c) Now consider a model using GINI, LIFE, and DEMOCRACY. Run the multiple regression and...

  • The Tire Rack, America's leading online distributor of tires and wheels, conducts extensive testing to provide...

    The Tire Rack, America's leading online distributor of tires and wheels, conducts extensive testing to provide customers with products that are right for their vehicle, driving style, and driving conditions. In addition, the Tire Rack maintains an independent consumer survey to help drivers help each other by sharing their long-term tire experiences. The following data show survey ratings (1 to 10 scale with 10 the highest rating) for 18 maximum performance summer tires (Tire Rack website, February 3, 2009). The...

  • This data was collected at a physician’s office. One measure of patient satisfaction is the likel...

    This data was collected at a physician’s office. One measure of patient satisfaction is the likelihood of a patient scheduling a return appointment. The goal is to keep the proportion of patients “unlikely” to schedule a return appointment to at most 25%. Test if the goal is being met. Use =.05. Clearly state your conclusion. DATA: Return Appointment     Employment Status       Age      Distance Unlikely            Employed         62        12.7 Unlikely            Unemployed     46        10.6 Likely    Employed         59        9.7 Unlikely            Unemployed     42        5.4 Likely    Employed        ...

  • 4.3 Analysis Assignment #4 Note 1: all assignments moving forward must adhere to the appropriate Six Ste...

    4.3 Analysis Assignment #4 Note 1: all assignments moving forward must adhere to the appropriate Six Step Process (SSP). As our study materials have specified, the SSP has 3 versions. Version 1 is to be used for all t-tests; for all correlation analyses and Version 3 is be used for all regression analyses. Note 2: The data sets for Q1, Q2 and Q3 below can be downloaded here. Week 4 Analysis Assignments.xlsx Q1: (30 points) Complete the following data analysis:...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT