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Problem 40 3456 12 A 54.0 g meter stick is balanced at its midpoint (50.0 cm, zero point is a left end of stick). Then a 250.

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Given: m=54g. 34cm 17cm m, =1259. [ m2 250g x 0.25 +0.25X17 Clockwise torques - 5 2x1000 = 0.00675 +0.00425 = 0.01 Ad kgf.m

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