Question

3 4 5 6 A 54.0-g meter stick is balanced at its midpoint (50.0 cm, zero point is a left end of stick). Then a 250.0-g weight is hung with a light string from the l2-67.0-cm point, and a 125-g weight is hung from the l1-16.0-cm point (the figure below). Calculate the clockwise and counterclockwise torques acting on the board due to the four forces shown about the following axes: F pivot 50 cm matick& mi т. 1) Calculate the clockwise torque if the axis is the 0-cm point. (Express your answer to three significant figures.) 1.888 N.m Submit 1.888 X Your submissions: Submitted: Thursday, November 21 at 7:48 PM Computed value: 1.888 Feedback: 2) Calculate the counterclockwise torque if the axis is the 0-cm point. (Express your answer to three significant figures.) 2.082 N m Submit

Answer 1

Page No. Date m2 A D. 50cm a Irot 67 cm At static equilibrium Ne force is zero (mit m+ m2g = R Fe R = (125+54 +250) x 10 x 908 croR = 402 N Sweet Selfie A m29x 67 - RASO loubouti

Date Date (1) A) clockwise = ( mix16+ mx 50+ M2 x 67 x 105 x 95 2 0.24 to 2 = (125X 16+ sux50 + 250x67) x 10-5x9.8 - 2.10 Nim (Tal counterclockwels - Rx 50 x 10-2 4. 2x rox 10-2 2.10 Nom = 2 Nom (3) (ec) clockwise ao m2gx 67 x 10 2 280x9 8X G7X 105 - 1064 Nom c) countaelockwise = migx (50-16) x 165 = 1250G. 8 X 34x10-5 - 0.417 Nim (B) Clockwth = | mix 84 + m x 50+ m2 x 33) 9.88105 Counterclockwis - (125x84 + 54x50 + 256733) x 9.8x10-5 - 2010 Nim (B) clockwise - - Rx50x10-2 402x tox 10-2 Sweet (O) selfie