Question

A uniform meter stick with a mass of 110 g is supported horizontally by two vertical strings, one at the 0-Cm mark and the other at the 90-cm mark(Figure 1). Part A Whaf is the tension in the string at 0 cm? Express your answer to two significant figures and include the appropriate units. F en Previous Answers Request Answer Submit X Incorrect; Try Again; One attempt remaining Part B Figure 1 of 1 What is the tension in the string at 90 cm? Express your answer to two significant figures and include the appropriate units Fo on Previous Answers Regdest Answer Submit x Incorrect: Try Again; 3 attempts remaining Provide Feedback

Answer 1

Let the tension in 0cm mark be T1 and tension in 90cm marke be T2

the weight of the stick will be acting in the middle of the stick and hence the weight will be acting at 50cm mark

balancing forces in vertical direction we get T1 + T2 = weight = mg = 0.11* 10 = 1.1 N

hence T1 + T2 = 1.1N

now balancing moment about 0cm mark we get

mg* 50 = T2 * 90

hence T2 = mg*50 / 90 = 0.611 N

hence T1 = 1.1 - 0.61 = 0.49N