Question

Please show all work! Thanks. The right answer should be C2H3O4Cl3.

You suspect that chloral hydrate has been used to “knock out” one of your colleagues due to its characteristic odour. A sample of his saliva yields 0.2843 g of an unknown organic substance. A quick combustion analysis yielded 0.1321 g of CO2, 0.0405 g of H2O, and 0.1598 of Cl2. Determine the empirical formula of the compound. If the molecular weight is between 370 g/mol and 380 g/mol, what is the molecular formula?

Answer 1

from the the given amount of information we have to find C, H, 0 and ce. Moles o CO₂ = Mass of co2 - Molar mass = 0.13219 = 0.003 mol 449 | mee. # I mal co2 is made up of 1 me of c 0.003 met co is made up of (0.003 mel c. Mass of c = Moles of cx melal mass = 0·003 mel & 12 glmel. = 10.036 g c Melus of H₂O = 0.0405 g = 0.00225 mel. 189 mett 1 met of H₂O is made up of 2 meles of H. 10:00225 meles of tho is made up of 2x 0.00225 ml of H. - 10.004s me of H Mass of H = 0.0045 ml x 1g/mol. 10:0045g of H # Meles of Ch 0.1598 g - 0.00 225 mol 70.9 gmelt In In 1 mol Cl₂ 2 moles of ce is present. 0.00225 mel = 2 mel ce x0.00225 melce 00225 mel a melch = 10.0045 mel ce.

О. ISBS + с). Mass of ce = 0.0045 melx 35.45 gmaly. --1 Sss a + Момо ҳам — (мом о кари) - ( мам в сян = (0-2 843 4) - (oo36 a to oo sa + baisas 4) 20-2843 8 - 0-20oo мах | ox{gen - Co843 81 Molts of Ox49th - 0.0 8434 2 - О.00S27 р. от 16g me! we have : 0.003 melc б:00Ч мр Н. О-обч, ме се. о: бO S21m01 б. Divide all by smallest number that is by 0.003. = а 6. до 2 /0-00 3 c 0.00Чs | b-003 - н О• ООЧs Job03 - се о. 00S21 [0:00 3 2 0 1 с'a-om 1.5 Н. 15 се. - 175 о Emperical formula = CH IS Clios 01.15.

Emberi cal formula mass = (12+ 105 X1 +1.5x39.45 + 1758 16) glmel = 94.675 g limel. Molecular formula = nx Emperical formula n = Moleculae formula mass Emperical formula mass. = 370 g/mel to 380 g (mel 94.675 g/mol Molecular Molecular formula = 4* (CHIS Clins 01.15) formula = C4 HG Cl Oy Molecular formula mass = (4x12 gmel") + (6 x 1g 1 me) + (6 x 35.45 g/ml) 67 x 16g/ml) = 378.7 gi mel It is in between 370 g/mel and 380 g/mel.

Right answer is C4H6Cl6O7 not C2H3Cl3O4