A 3.9−μF capacitor is connected to a 8.8−V battery. What is the
magnitude of the charge on each plate?
Q = μC.
Then C=Q/V
SO,
Q=CV
Q=3.9*10^-12*8.8
Q=3.43*10^-11 C
Q=3.43 uC Answer
I hope help you !!
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