Question

A large candy manufacturer in Slidell produces, packages, and sells packs of candy targeted to weigh...

A large candy manufacturer in Slidell produces, packages, and sells packs of candy targeted to weigh 500 grams. The weight of a pack of candy is normally distributed with the mean μ=500 grams, but Parker Sanderson, a quality control manager working for the company, was concerned that the variation in the actual weights of the targeted 500-gram packs was larger than acceptable. That is, he was concerned that some packs weighed significantly less than 500-grams and some weighed significantly more than 500 grams. In an attempt to estimate σ, the standard deviation of the weights of all of the 500-gram packs the manufacturer makes, he took a random sample of n = 24 packs off of the factory line. The random sample yielded a sample standard deviation of 23.6 grams.

(1) Construct a 95% confidence interval of the unknown population standard deviation σ.

(2) Test the alternate hypothesis that the population standard deviation σ is significantly larger than 20 grams.

(i) Alternatives

Select one:

H0: σ ≤ 20                    H1: σ > 20

H0: σ2 ≤ 20 H1: σ2 > 20

H0: σ ≥ 20                    H1: σ < 20

H0: σ = 20                    H1: σ ≠ 20

None of the other four

(ii) Test statistic

Select one:

χ* = 5.66

χ* = 24.71

χ* = 32.03

χ* = 43.21

None of the other four

(iii) p-value

Select one:

Approximately 0.01

Approximately 0.05

Approximately 0.10

Approximately 0.20

Approximately 0.025

(iv) What is the conclusion if the level of significance is α=0.05?

Select one:

Conclude H0 that the population standard deviation σ is larger than 20 grams.

Conclude H0 that the population standard deviation σ is no larger than 20 grams.

Conclude H1 that the population standard deviation σ is larger than 20 grams.

Conclude H1 that the population standard deviation σ is no larger than 20 grams.

None of the other four

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Answer #1

1)

The 95% confidence interval is 336.4378 < sigma^2 < 1095.951

2)

The provided sample variance is s2 556.96 and the sample size is given by n 24. (1) Null and Alternative Hypotheses The following null and alternative hypotheses need to be tested Ho : σ-400 Ha : σ2 > 400 This corresponds to a right-tailed test, for which a Chi-Square test for one population variance will be (2) Rejection Region Based on the information provided, the significance level is a 0.05, and the the rejection region for this right-tailed test is R = {x X > 35.172) The Chi-Squared statistic is computed as follows: (n 1)s (24 1) 556.96 32.025 400 Since it is observed that X-32.025 < Хіт-35.172, it is then concluded that the null hypothesis is not rejected. It is concluded that the null hypothesis Ho is not rejected. Therefore, there is not enough evidence to claim that the population variance σ2 is greater than 400, at the 0.05 significance level. The 95% confidence interval is 336.4378 < σ2 < 1095.951.

hypothesis

A) H0: σ ≤ 20                    H1: σ > 20

TS = 32.03

p-value = 0.0996

Approximately 0.10

we fail to reject the null hypothesis

Conclude H0 that the population standard deviation σ is no larger than 20 grams.

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