Question

Suppose a software company finds that the number of errors in its software per 1,000 lines of code is described by a Poisson distribution. Furthermore, it is found that there is an average of 8 errors per 1,000 lines of code. Letting x denote the number of lines of code between successive errors: (Round your answers to 4 decimal places.) (a) Find the probability that there will be at least 400 lines of code between successive errors in the company's software. (b) Find the probability that there will be no more than 100 lines of code between successive errors in the company's software. P.

Answer 1

For 1000 lines of code So for 400 lines of rode 2000 - 2 - 400 x8 = 3.2 1000 and for yoo lines of code 12 = 100648=0.80 Plxax)=élge here n = 3.2 B! @ PLx7,2)=81- plx=0) Finelar - se! a)- €3213.27 : Ol = 1 - 0.0408 - 10.9592 16 in this case 72 = 0.80 la PL x < 2) = pqxa Bei hes € x 0.80 : -0.4493