Predict which solutions will have a higher electrical conductivity: 14.22 g of cobalt (II) nitrate in 57.8 mL of water or 9.528 g of copper (II) chloride in 32.9 mL of water.
molarity of cobalt(II) nitrate = [mass/ molarmass]/V(L)
= [14.22g/182.94g/mol)/0.0578L
=1.345 mol/L
Co(NO3)2 (aq) ----------> Co+2 + 2NO3-
1.345 2x1.345
Total ions = 1.345 + 2.690 = 4.035moles of ions
molarity of copper (II) chloride = [ 9.528g/134.45g/mol] /0.0329L
=2.153 mol/L
As the molarity of CuCl2 > Co(NO3)2 , both give te same number of ions, CoCl2 has higher electrical conductivity than cobalt nitrate.
Predict which solutions will have a higher electrical conductivity: 14.22 g of cobalt (II) nitrate in...
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