Question

14. If a solution is made by dissolving 14.5 g of Fe(NO3)3 in 455 ml of water, what is the mass percent of iron and nitrate in this solution? Assume 1.00 g/ml density of the water. 4 pts

Answer 1

Volume of waten = V = 45smL 1.0/mL Density of solution (e) Amount of &ubun PXV water 1009/mL X 455mL 11 4s53 Amount of Fe(No3l3 14.52 4ss t 4-5)a 469.54 1 Total mass Of Soution LJ 241.869/mole Molan mass of FelNo

1 No of moles of Fe(Noals > 14-52 a 41-8681mob 11 Fe (No Fest 3No (ag) No of mole of Feat No of moles of No ion Produce d O-0539mob 3 Xo.o59gmo 1 O-1398m01e Molar mass Amaunt of Fe = of fe 55-845gmal O.o599molx S-84531moh 3-34S A of No Molan masS ২.০০4৭glmdl in solution Amount of No paeent E 0.13 98mob x62.00493mo । 1७ 2

Amount of Fe Pneentloo Pencent of Fe Mass Total ma ss D80lution 3-3459xloo 469- Mass Pencent of Fe Anausta Amaunt of No pnegent1oo Totaf amount of salution Mass Percent of N 463-59 Anauser Mass Percent of N