Determine the molality of a solution made by dissolving 0.239 moles of glucose in 546 mL of water. Assume the density of water is 1.00 g/mL.
m glucose
m(solvent)= density * volume
= 1.00 g/mL * 546 mL
= 546 g
= 0.546 kg
use:
Molality,
m = number of mol / mass of solvent in Kg
=(0.239 mol)/(0.546 Kg)
= 0.4377 molal
Answer: 0.438 molal
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