Question

Determine the molality of a solution made by dissolving 0.575 moles of (NH4)2CO3 in 3311 g of H2O. m (NH4)2CO3

Determine the molality of a solution made by dissolving 0.575 moles of (NH4)2CO3 in 3311 g of H2O.

m (NH4)2CO3

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Answer #1

m(solvent)= 3311 g

= 3.311 kg

use:

Molality,

m = number of mol / mass of solvent in Kg

=(0.575 mol)/(3.311 Kg)

= 0.1737 molal

Answer: 0.174 molal

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Determine the molality of a solution made by dissolving 0.575 moles of (NH4)2CO3 in 3311 g of H2O. m (NH4)2CO3
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