Determine the molality of a solution made by dissolving 0.575 moles of (NH4)2CO3 in 3311 g of H2O.
m (NH4)2CO3
m(solvent)= 3311 g
= 3.311 kg
use:
Molality,
m = number of mol / mass of solvent in Kg
=(0.575 mol)/(3.311 Kg)
= 0.1737 molal
Answer: 0.174 molal
Determine the molality of a solution made by dissolving 0.575 moles of (NH4)2CO3 in 3311 g of H2O. m (NH4)2CO3
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