A.
Determine the molality of a solution made by dissolving 42.6 g of CH3OH in 716 g of H2O.
Answer:_____m CH3OH
B.
Determine the molality of a solution made by dissolving 0.568 moles of (NH4)2CO3 in 3366 g of H2O.
Answer:_____m (NH4)2CO3
C.
Determine the molality of a solution made by dissolving 0.519 moles of CH3OH in 746 g of ethanol.
Answer:___m CH3OH
A. Determine the molality of a solution made by dissolving 42.6 g of CH3OH in 716 g of H2O. Answer:_____m CH3OH B. Deter...
Determine the molality of a solution made by dissolving 0.575 moles of (NH4)2CO3 in 3311 g of H2O. m (NH4)2CO3
Determine the molality of a solution made by dissolving 0.365 moles of CH3OH in 636 g of ethanol. m CH3OH
Determine the molality of a solution made by dissolving 44.1 g of CH3OH in 737 g of H2O. m CH3OH
Determine the molality of a solution made by dissolving 0.134 moles of glucose in 471 mL of water. Assume the density of water is 1.00 g/mL. Determine the molality of a solution made by dissolving 28.1 g of CH3OH in 513 g of H20.
Determine the mass percent composition of a solution made by dissolving 4.91 moles CH3OH in 3.01 L of H2O
Determine the molality of a solution made by dissolving 0.239 moles of glucose in 546 mL of water. Assume the density of water is 1.00 g/mL. m glucose
Determine the molality of a solution prepared by dissolving 1.00 moles of CaBr2 in 23.0 moles H2O.
Determine the mass percent composition of a solution made by dissolving 5.31 moles CH3OH in 3.21 L of H,O. % CH3OH
Determine the molality of an aqueous solution prepared by dissolving 0.224 moles of LiBr in 27.4 moles of H2O.
1. Determine the molality of a solution prepared by dissolving 4.95 g of potassium chloride in 70 g of water. Enter your answer to 2 decimal places 2. Determine the molality of a solution of benzene dissolved in toluene (methylbenzene) for which the mole fraction of benzene is 0.132. Give your answer to 2 decimal places. 3. How many moles of solute particles are present in 7.89 mL of 0.458 M K2SO4? When you have your answer, take the LOG...