Question

What is the molality of a 50% by mass aqueous solution of glucose (molar mass = 180 g/mol) Assume the density of water = 1.00 g/mL

		0.00554 m
		1.00 m
		5.56 m
		2.34 m

Answer 1

molality = moles of solute / mass of solvent in kg

mass of solute = 50 % i.e 50 grams

mass of solvent = 50g = 0.050 Kg

mass of solution = 100 g

moles of solute = 50 / 180 => 0.278 moles

molality = 0.278 moles / 0.050 kg

=> 5.56 m

answer => 5.56 m