Score: E-peild Imagine a proton moving initially at 2.1x 10 m/s in the positive direction of...
Imagine a proton moving at 2.1 x 10m/s in the positive direction of the x-axis. It moves in a field-free space until it passes by the origin, x = 0, where it encounters an electric field directed along the x-axis. (The y and z components of the field are zero everywhere). The electric potential, V(x), associated with this field is shown in the graph below. 200 Hlectrical (V) 100 50 0 0 10 20 30 40 50 60 70 Position...
A proton moving in the positive x direction with a speed of 9.1 105 m/s experiences zero magnetic force. When it moves in the positive y direction it experiences a force of 1.8 10-13 N that points in the positive z direction. Determine the magnitude and direction of the magnetic field. magnitude T
An electron moving with a speed of 8.8 x105 m/s in the positive z direction experiences zero magnetic force. When it moves in the positive x direction it experiences a force of 2.4 x10-13 N that points in the negative y direction. What is the magnitude and direction of the magnetic field? Magnitude: B= _____________T Direction: Magnetic field is pointed in ____________(indicate positive or negative) direction of ______________(indicate which axis i.e. x, y, or z) axis.
A proton moves at 4.30 x 10 m/s in the horizontal direction. It enters a uniform vertical electric field with a magnitude of 7.90 10 N/C. Ignore any gravitational effects. (a) Find the time interval required for the proton to travel 4.70 cm horizontally. (b) Find its vertical displacement during the time interval in which it travels 4.70 cm horizontally (c) Find the horizontal and vertical components of its velocity after it has traveled 4.70 cm horizontally Part 1 of...
A proton is projected in the positive x direction into a region of uniform electric field E (-5.20 x 10) i N/C at t 0. The proton travels 6.00 cm as it comes to rest. (a) Determine the acceleration of the proton magnitude directionSelect m/s (b) Determine the initial speed of the proton. magnitude direction-Select m/s (c) Determine the time interval over which the proton comes to rest.
A proton is projected in the positive x direction into a region of uniform electric field E = (-6.90 × 105) Î N/C at t = 0, The proton travels 6.90 cm as it comes to rest. (a) Determine the acceleration of the proton magnitude direction | Select- m/s2 (b) Determine the initial speed of the proton. magnitude direction | Select- m/s (c) Determine the time interval over which the proton comes to rest.
A proton, initially traveling in the +x-direction with a speed of 5.15×105 m/s , enters a uniform electric field directed vertically upward. After traveling in this field for 3.96×10−7 s , the proton’s velocity is directed 45 ∘ above the +x-axis. Part A What is the strength of the electric field?
A proton is projected in the positive x direction into a region of uniform electric field = (-5.70 ✕ 105) î N/C at t = 0. The proton travels 7.50 cm as it comes to rest. (a) Determine the acceleration of the proton. magnitude m/s2 (b) Determine the initial speed of the proton. magnitude m/s (c) Determine the time interval over which the proton comes to rest. s
proton is projected in the positive x direction into a region of uniform electric field E with arrow = (-5.90 ✕ 105) î N/C at t = 0. The proton travels 6.00 cm as it comes to rest. (1)Determine the acceleration of the proton.&direction (2) Determine initial speed of proton &direction (3)Determine the time interval over which the proton comes to rest.
A proton is moving at a speed of 1.5 x 10^5 m/s when it travels through a potential difference and accelerates uniformly to a speed of 4.5 x 10^6 m/s. What was the value of the potential difference through which the proton traveled. If the distance the proton traveled was 50 cm, what was the magnitude of the electric field?