Question

9) A riple of mass, 3kg, at rest, fires a bullet of 200g with a speed of 100 m/s, what is the recoil speed of the rifle? I I

Answer 1

if you have any confusion then please ask me in the comment box.

I het mass of rifle m, = 3 kg initial speed of riflete, o final speed (Recoil speed of rifte) v = ? mass of bullet M2 - 200g = 0.2 kg initial speed of bullet U2=0 final speed of bullet V2 = 100 mis Now from conservation of momentum Initial momentum = Final momentum. mu, + Mauz = mv,+ M₂ V2 m, xo + m₂ xo = 3xv, + 0.2 x 100 o=3v1 + 20 v=-20 = -6.67 m/s. [v=-6.67 mis means the recoil speed of rifle will be 6.67 m/s just opposite to the direction of bulut.

Thank you