Question

Problem # 4 The 3000 kg cable car shown in figure descends a 200 m-high hill. In addition to its brakes, the cable car controls its speed by pulling a 2500 kg counterweight up the other side of the hill. The rolling friction of both the cable car and the counterweight are negligible. Counterweight 200 m 25° 35 A. Draw the free body diagrams of cable car (call it m,) and the counterweight (call it m2) mass. Draw component diagrams. B. Choose an appropriate set of axes and write Newton's laws for both masses in x and y directions. C. Solve the equations and find out how much braking force does the cable car need to descend at a constant speed?

Answer 1

MF 3000 Kg , h=200m , m= 2500 kg mag snart 29 Co2ro B) m, Oyx = mig sin35-T Ni= mig cos35 m292x = T-mog sin 25° Na = mag cos 25 (e) Since, length of cable is const. C. QiQ = A2X= ma- mig sin3s - T 3000 a = 16863.15-T - 2500 a - T-10354.15 - Adding een-(i) and (1) 5500 a = 6509 Q- 1.183 m/s2 0 (0) .: braking force required id Fam, a = 3000 x1-183 F = 3550.36 N 1 w Braking force