Question

The 1930 kg cable car shown in the figure descends a 200-m-high hill. In addition to its brakes, the cable car controls its speed by pulling an 1760 kg counterweight up the other side of the hill. The rolling friction of both the cable car and the counterweight are negligible. (Figure 1) Part A How much braking force does the cable car need to descend at constant speed? Express your answer with the appropriate units. Value Units Submit Request Answer Part B One day the brakes fail just as the cable car leaves the top on its downward journey. What is the runaway car's speed at the bottom of the hill? Express your answer with the appropriate units. HÅR O O ? Figure (< 1 of 1 > Value Units Counterweight Submit Request Answer Lee 200 m 30° I . 2007 Provide Feedback

Answer 1

The Answer! Given That Partain mi= 1930 kg m2 = 1760 kg h= 200 m Breaking force Famig sina, - megsin Oz 1930 9.818$n(58) – 1760x9.815°C20X360=9.81m)527 OF = 3561. 44 N 182=28 Pears. The Break fails. The car acceleration at 5. на a: Flm F = 3561.47 N CO2 = 20 Parti m=mitm2 3561.47 1930 +1760 a=0.465 m/sec2 | Now, The length 200 sin (so) PL The Loh/sino, La loom] velocity JaaL Jaxo.965x400 Larv= 27.78 m/sec