Proton is released from rest so u = 0 m/s = initial speed
E = 2.18 x 105 N/C
F = E*q
F = 2.18x105*(1.6x10-19)
F = 3.488 x 10-14 N
and we also know that
F=m*a
a = F/m
a = (3.488 x 10-14)/(1.672 x 10-27)
a = 2.086124 x 1013 m/s2
using a in
v2 = u2 + 2*a*s
v = (2*a*s)
v = (2*2.086124 x 1013*0.011)
v = 677456.54 m/s
v = 6.77 x 105 m/s
(b)
same for this part s = 0.14 m
v2 = u2 + 2*a*s
v = (2*a*s)
v = (2*2.086124 x 1013*0.14)
v = 2416846.77 m/s
v = 2.41 x 106 m/s
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