Question

earning & Assessment A proton is released from rest in a uniform electric field of magnitude 1.6 × 103 V/m di- rected along the positive r axis. The proton undergoes a displacement of 0.3 m in the di io of theethe lds shown in the figure. 1.6 × 105 V/m 0.3 m Find the change in the electric potential if the proton moves from the point A to B. The mass of a proton is 1.672623 × 10-27 kg. Answer in units of V 003 (part 2 of 3) 10.0 points Find the change in potential energy of the proton for this displacement. Answer in units of J. 004 (part 3 of 3) 10.0 points Apply the principle of energy conservation to find the speed of the proton after it has moved 0.3 m, starting from rest. ab Answer in units of m/s

Answer 1

Given E = 1.6 times 10^5 v/m d = 0.3m delta v = E.d = 1.6 times 1065 times 0.3 implies 0.48 times 10^3 v (b) P-E = q delta v = 1.6 times 10^-15 times 0.48 times 10^3 = 0.768 times 10^-16 J^- b (c) Using conservation of energy k-E = electric P.E 1/2 times 1.67 times 10^-27 times u^2 = 0.768 times 10^-16 u^2 = 2 times 0.768 times 10^- 16/1.67 times 10^-27 u^2 = 0.919 times 10^11 u = 3.03 times 10^5 m/sec