An element in its ground state has electron configuration: [Ar]4s23d104 What is this element? Answer: Check

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Answer 1

Answer #1

Answer:

Ground State Electronic Configuration : [Ar] 4s² 3d¹⁰ 4p⁴.

Ar is symbol for Argon nobel gas with 18 hence

[Ar] $\equiv$ 18 electrons and

$\therefore$ Total Number of electrons = 18 + 2 "4s electrons"+ 10 "3d electrons"+ 4 "4p electrons".

$\therefore$ Total Number of electrons = 18 + 2 + 10 + 4 = 34.

With 34 electrons its a Selenium element.

The element is SELENIUM (Se)

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Answer 2

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