At a high school debate tournament, half of the teams were asked
to wear suits and ties and the rest were asked to wear jeans and
t-shirts. The results are given in the table below. Test the
hypothesis at the 0.05 level that the proportion of wins is the
same for teams wearing suits as for teams wearing jeans.
a. critical value
b. test statistic
Answer)
Ho : P 1 = P 2
Ha : P1 not equal to P2
P1 is for suits
P2 is for t shirt
N1 = 50, P1 = 22/50
N2 = 50, P2 = 28/50
First we need to check the conditions of normality that is if n1p1 and n1*(1-p1) and n2*p2 and n2*(1-p2) all are greater than equal to 5 or not
N1*p1 = 22
N1*(1-p1) = 28
N2*p2 = 28
N2*(1-p2) = 22
All the conditions are met so we can use standard normal z table to conduct the test
Test statistics z = (P1-P2)/standard error
Standard error = √{p*(1-p)}*√{(1/n1)+(1/n2)}
P = pooled proportion = [(p1*n1)+(p2*n2)]/[n1+n2]
After substitution
Test statistics z = -1.2
To find critical value first we need to divide the alpha (0.05) into two parts
As our test is two tailed
0.05/2 = 0.025
From z table, P(z<-1.96) = P(z>1.96) = 0.025
So critical values are -1.96 and 1.96
At a high school debate tournament, half of the teams were asked to wear suits and...
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