23/10+41/5+2/3 reduce to the lowest term
23 + 123 + 10/10
= 156/10
=78/5
78/5 is the lowest term.
This is the lowest term because it can't be divided any further.
add the following and reduce to the lowest term: 2 3/10 + 4 1/5 + 2/3
3 5/6 - 5 2/3 and reduce to lowest
3 5/6 + 5 2/3 and reduce to lowest form
Add the following and reduce to the lowest terms 2/3 + 5/6
reduced to the lowest term 7 1/7 - 2 5/6
3 5/6 + 5 2/3 to the lowest form
2 1/6 - 1 1/4 and reduce to lowest form
Show that the pair of vectors is perpendicular, -41 -23 and 41 - Sj To show that -41 - 2j and 41 - Bj are perpendicular, we must show that their dot product equals (-41 - 2) (41 - 8)) = (-4)(4) + ( (-3) We see that the dot product is Therefore, the vectors are perpendicular
Perform the indicated operation. Where possible, reduce the answer to its lowest terms 3) 9.6
4 1/4 - 1 3/4 to the lowest term