28. For the reaction 2 SO2(g) + O2(g) → 2 S03(), a. Determine the expression for...

Question

Question

Answer 1

Answer #1

SoJy Guiven slecen 2502(8) + 02191- 2 Soz (8) rate of reach (g) = rate of dissofference of so, ore = rate of affeorance of so

Answer 2

Similar Homework Help Questions

2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of...

2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of each of the following changes on the number of moles of S03 present in the mixture at equilibrium Decreasing the volume of the system Adding oxygen to the equilibrium mixture Raising the temperature of the system Decreasing the pressure of the system Adding a catalyst 2 SO2 (g) + O2 (g) = 2 SO3 (g) + Energy Predict the effect of each of the...
For the equilibrium reaction, 2 S03 - 2 SO2 (g) + O2 (g), Kc is 4.08...

For the equilibrium reaction, 2 S03 - 2 SO2 (g) + O2 (g), Kc is 4.08 x10-3 at 1000 K. Calculate the value for Kp. (R 0.0821 L.atm/ mol.K) A. 9.60 B. 2.99 OC. 4.97 x 10-5 OD.0.335
Determine the order for [SO] in the following reaction 2 SO(g) + O2(g) - 2 SO2(g)...

Determine the order for [SO] in the following reaction 2 SO(g) + O2(g) - 2 SO2(g) [SO]i (M) [O] (M) Initial Rate (MS-1) 0.120 0.100 1.50 x 10-3 0.240 0.100 3.00 x 10-3 0.120 0.200 1.20 x 10-2 QUESTION 27 Determine the order for [O2) in the following reaction 2 SO(g) + O2(g) - 2 SO2(g) [SO]i (M) [O2li (M) Initial Rate (Ms-1) 0.120 0.100 1.50 x 10-3 0.240 0.100 3.00 x 10-3 0.120 0.200 1 1.20 x 10-2 QUESTION...

1. Consider the following reaction at equilibrium. 4 FeS2(s) + 11 O2(g) ⇌ 2 Fe2O3(s) + 8 SO2(g)...

1. Consider the following reaction at equilibrium. 4 FeS2(s) + 11 O2(g) ⇌ 2 Fe2O3(s) + 8 SO2(g) a. What will happen if the pressure increased? b. What will happen if the concentration of FeS2(s) is decreased? 2) The following reaction is exothermic: What direction will the equilibrium shift if the following changes are made? 2 SO2(g) + O2(g) ⇌ 2 SO3(g) a) Raising the temperature b) Adding SO3 c) Removing O2 d) Decreasing the volume
3. Consider the following reaction: 2 SO2 (g) + O2 (g) → 2 SO3 (g) AH.x...

3. Consider the following reaction: 2 SO2 (g) + O2 (g) → 2 SO3 (g) AH.x = -197.6 kJ a. If 285.3 g of SO2 is allowed to react with 158.9 g of O2, what is the limiting reactant and theoretical yield of SO3 in liters if the reaction is performed at 315 K and 50.0 mmHg? How much of each reactant remains at the end of the reaction? [10] LR: SO TY: SO2 remaining: O2 remaining: Imol soa 64.000log...
The reaction and equilibrium constant are provided. 2 SO2(g) + O2(g) 92 SO3(g) K = 5.8...

The reaction and equilibrium constant are provided. 2 SO2(g) + O2(g) 92 SO3(g) K = 5.8 x 103 Which direction will the reaction proceed if [502] = 0.015 M. [02] = 0.010 Mand (SO3) = 0.200 M? no shift shifts to make more product shifts to make more reactant

Calculate Δ G for the reaction 2 SO2 (g) + O2 (g) → 2 SO3 (g)...

Calculate Δ G for the reaction 2 SO2 (g) + O2 (g) → 2 SO3 (g) when P of SO2 = 0.500 atm, P of O2 = 0.0100 atm, and P of SO3 = 0.100 atm. The value for Δ G^o for this reaction at 298 K is -141.6 kJ. ΔG = ???? kJ I got -160.9 kj but it is incorrect.
What is AS for the reaction SO2(g) + NO2(g) + S03(g) + NO(g? Substance S'(J/K.mol) SO2(9)...

What is AS for the reaction SO2(g) + NO2(g) + S03(g) + NO(g? Substance S'(J/K.mol) SO2(9) 248.5 256.2 NO(g) 210.6 NO2() 240.5 SO3(g) (8 00:51:01 eBook Multiple Choice 0 O 53.6 J/K mol 0 -53.6 J/K mol 0 -22.2 J/K.mol 0 474.8 J/K. mol
Calculate AG for the reaction 2 SO2 (g) + O2 (g) → 2 SO3 (g) when...

Calculate AG for the reaction 2 SO2 (g) + O2 (g) → 2 SO3 (g) when P of SO2 = 0.500 atm, P of O2 = 0.0100 atm, and P of SO3 = 0.100 atm. The value for AGº for this reaction at 298 K is -141.6 kJ. AG= O * kJ Is this reaction spontaneous or non-spontaneous under these conditions? Spontaneous or non-spontaneous? spontaneous

Given the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g) Starting with 0.100 M of SO2...

Given the reaction: 2 SO2(g) + O2(g) ⇌ 2 SO3(g) Starting with 0.100 M of SO2 and 0.050 M of O2, which value of K should be used and why? a. KC because the chemicals are in the gas phase. b. KP because the concentrations are in Molarity. c. KP because the chemicals are in the gas phase. d. KC because the concentrations are in Molarity.