Question

Given: Concentration of KMnO4= 4.19% Initial mass of KMnO4, solution in pipet= 66.8052g Final mass of...

Given:

Concentration of KMnO4= 4.19%

Initial mass of KMnO4, solution in pipet= 66.8052g

Final mass of KMnO4, solution in pipet= 65.9755g

Mass of KMnO4 solution used= 0.8297 g

Initial mass of H2O2 soln in pipet= 56.3832 g

Final mass of H2O2 soln in pipet= 55.815g

Mass of H2O2 solution used= 0.568g

Observations of rxn: brown precipitate

Using the mass and concentration of the KMnO4 solution, calculate the mass of KMnO4 used in the titration.

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Answer #1

Let 'x' be the amount of KMnO​​​4 that is used in the reaction. So, 4.19= (x/.8297)×100

Or, x = . 034

As x amount of KMnO​​​4 reacts out of .8297 g given because the percentage purity or concentration of it is 4.19%... the compound is not 100% pure.

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