Homework Answers
4)
Molar mass of HCO3,
MM = 1*MM(H) + 1*MM(C) + 3*MM(O)
= 1*1.008 + 1*12.01 + 3*16.0
= 61.018 g/mol
use:
mass of HCO3,
m = number of mol * molar mass
= 7.5*10^-4 mol * 61.02 g/mol
= 0.04576 g
Now use:
Mass % of HCO3- = mass of HCO3 * 100 / mass of sample
= 0.04576 * 100 / 0.4312
= 11 %
Rounding to 2 significant figures because 0.00085 moles has only 2 significant figures
Answer: 11 %
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I Need the pre-lab
Questions, please
An Alka-Seltzer tablet consists of NaHCOs (sodium bicarbonate), citric acid (H3C&HsO; citric acid is triprotic), aspirin and other inert ingredients. When dissolved in water, citric acid and NaHCO3 components react as follows: In the first part of the experiment, we will determine the mass of NaHCO in a tablet of Alka Seltzer. To do this, we will use a known mass of a powdered sample of Alka-Seltzer and determine the mass of CO2 gas...
help
with remaining calculations please
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