Total energy emitted in transition from n th excited state to ground state by one atom = 13.6(1 - 1/(n+1)^2 )
Hence 48/49 = ( 1 - 1/(n+1)^2 )
n = 6
Maximum possible photons emitted by an atom, as it comes down to ground state from n th excited state
= n(n+1)/2 = 21
Maximum possible photons emitted by 100 atoms = 2100
Option b is correct.
A sample of monoatomic hydrogen gas contains 100 atoms and all the atoms are in nth...
5. (2 points) How many photons are emitted from neon gas if all the atoms of a 20.18 g sample relax from an n 6 excited state back to an n 1 ground state? A. 7.221 x 1024 B. 6.022 x 102 C. 5.022 x 1022 D. 3.011 x 1024 E. 1.507 x 103
Lab Section: Experiment #11: The Atomic Spectrum of Hydrogen Advanced Study Assignment 1. Found in the gas phase, the beryllium trication, Be has an energy level formula analogous to that of the hydrogen atom, since both species have only one electron. The energy levels of the Belon are given by the equation E, = -2100-kl/mole n = 1.2.3. - Calculate the energies in kl/mole for the four lowest energy levels of the Belon. a kl/mole kl/mole kJ/mole kl/mole b. One...